Gujarati
p-Block Elements - I
medium

The type of hybridisation of boron in diborane is

A

$sp$ - hybridisation

B

$s{p^2}{\rm{ - }}$ hybridisation

C

$s{p^3}{\rm{ - }}$ hybridisation

D

$s{p^3}{d^2}{\rm{ - }}$ hybridisation

Solution

Boron has three valence electrons, so it is supposed to make $3$ bonds in a molecule with hybridization, $sp ^2$ as only s and two $p$ orbitals are used in hybridization and last $p$ orbitalis vacant.

But diborane, $B _2 H _6$ contains two electrons each, three centred bonds. Each Boron atom is in a link with four hydrogen atoms. This makes tetrahedral geometry.

Hence, each Boron atom is $sp ^3$ – hybridized.

Standard 11
Chemistry

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