The type of hybridisation of boron in diboran | vedclass

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Question

Boron has three valence electrons, so it is supposed to make $3$ bonds in a molecule with hybridization, $sp ^2$ as only s and two $p$ orbitals are us

Vedclass · Accepted Answer

$s{p^3}{\rm{ - }}$ hybridisation

Vedclass · Answer

Boron has three valence electrons, so it is supposed to make $3$ bonds in a molecule with hybridization, $sp ^2$ as only s and two $p$ orbitals are used in hybridization and last $p$ orbitalis vacant.

But diborane, $B _2 H _6$ contains two electrons each, three centred bonds. Each Boron atom is in a link with four hydrogen atoms. This makes tetrahedral geometry.

Hence, each Boron atom is $sp ^3$ - hybridized.

List$-I$	List$-II$
$(a)$ $\mathrm{NaOH}$	$(i)$ Acidic
$(b)$ $\mathrm{Be}(\mathrm{OH})_{2}$	$(ii)$ Basic
$(c)$ $\mathrm{Ca}(\mathrm{OH})_{2}$	$(iii)$ Amphoteric
$(d)$ $\mathrm{B}(\mathrm{OH})_{3}$
$(e)$ $\mathrm{Al}(\mathrm{OH})_{3}$

The type of hybridisation of boron in diborane is

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