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1.Units, Dimensions and Measurement
normal
The unit of electric field is not equivalent to
A$N/C$
B$J/C$
C$V/m$
D$J/C - m$
Solution
(b)By unit and $dimension -electric$ feild.
$\frac{N}{C}=\frac{\text {volt}}{\text {meter}}=\frac{J}{c-m t}$
Therefore, dimensions of $E=M L T^{-3} A^{-1}$
which is a vector quantity.
So, the correct answer is $B: J / C$
Because, it gives the answer work done per unit charge which is called Potential.
$\frac{N}{C}=\frac{\text {volt}}{\text {meter}}=\frac{J}{c-m t}$
Therefore, dimensions of $E=M L T^{-3} A^{-1}$
which is a vector quantity.
So, the correct answer is $B: J / C$
Because, it gives the answer work done per unit charge which is called Potential.
Standard 11
Physics
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