Value of sin ^{2} 30-tan 45+cos ^{2} 60-cot 90 is ........

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8. Introduction to Trigonometry

easy

The value of $\sin ^{2} 30-\tan 45+\cos ^{2} 60-\cot 90$ is ........

A

$-\frac{1}{2}$

B

$1$

C

$\frac{3}{2}$

D

$2$

Solution

$\sin ^{2} 30-\tan 45+\cos ^{2} 60-\cot 90$

$=\left(\frac{1}{2}\right)^{2}-1+\left(\frac{1}{2}\right)^{2}-0$ $\left(\because \sin 30=\cos 60=\frac{1}{2}\right.$ and $\left.\tan 45=1\right)$

$=\frac{1}{4}-1+\frac{1}{4}=\frac{1}{2}-1=-\frac{1}{2}$

Standard 10

Mathematics

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