Value of power dissipated across zener diode left( V _{ z }=15 V right) connected in circuit as show

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14.Semiconductor Electronics

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The value of power dissipated across the zener diode $\left( V _{ z }=15 V \right)$ connected in the circuit as shown in the figure is $x \times 10^{-1}$ watt.

The value of $x ,$ to the nearest integer, is ..............

A

$5$

B

$4$

C

$2$

D

$6$

(JEE MAIN-2021)

Solution

Voltage across $R _{ S }=22-15=7 V$

Current through $R _{ S }= I =\frac{7}{35}=\frac{1}{5} A$

Current through $90 \Omega= I _{2}=\frac{15}{90}=\frac{1}{6} A$

Current through zener $=\frac{1}{5}-\frac{1}{6}=\frac{1}{30} A$

Power through zener diode

$P = VI$

$P =15 \times \frac{1}{30}=0.5 watt$

$P =5 \times 10^{-1} watt$

Standard 12

Physics

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