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2.Motion in Straight Line
medium
The velocity $v$ of a particle as a function of its position $(x)$ is expressed as $v=\sqrt{c_1-c_2 x}$, where $c_1$ and $c_2$ are positive constants. The acceleration of the particle is
A$c_2$
B$-\frac{c_2}{2}$
C$c_1-c_2$
D$\frac{c_1+c_2}{2}$
Solution
(b)
$v^2=c_1-c_2 x$, comparing with $v^2=u^2+2 a s$, we have $a=-\frac{c_2}{2}$
$v^2=c_1-c_2 x$, comparing with $v^2=u^2+2 a s$, we have $a=-\frac{c_2}{2}$
Standard 11
Physics
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