2.Motion in Straight Line
hard

The velocity-displacement graph describing the motion of a bicycle is shown in the figure.

The acceleration-displacement graph of the bicycle's motion is best described by

A
B
C
D
(JEE MAIN-2021)

Solution

For $0 \leq x \leq 200$

$v = mx + C$

$v =\frac{1}{5} x +10$

$a =\frac{ vdv }{ dx }=\left(\frac{ x }{5}+10\right)\left(\frac{1}{5}\right)$

$a =\frac{ x }{25}+2 \Rightarrow Straight$ line till $x =200$

for $x>200$

$v =$ constant

$\Rightarrow a=0$

Hence most approriate option will be $(a)$

Standard 11
Physics

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