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2.Motion in Straight Line
hard
The velocity-displacement graph describing the motion of a bicycle is shown in the figure.
The acceleration-displacement graph of the bicycle's motion is best described by

A

B

C

D

(JEE MAIN-2021)
Solution

For $0 \leq x \leq 200$
$v = mx + C$
$v =\frac{1}{5} x +10$
$a =\frac{ vdv }{ dx }=\left(\frac{ x }{5}+10\right)\left(\frac{1}{5}\right)$
$a =\frac{ x }{25}+2 \Rightarrow Straight$ line till $x =200$
for $x>200$
$v =$ constant
$\Rightarrow a=0$
Hence most approriate option will be $(a)$
Standard 11
Physics