The velocity of a particle depends upon the t | vedclass

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Question

$\mathrm{v} ightarrow \mathrm{bt} ightarrow \mathrm{bt}=\frac{	ext { distance }}{	ext { time }} ightarrow \mathrm{b} =\frac{	ext { distance }

Vedclass · Accepted Answer

distance, acceleration, distance, time

Vedclass · Answer

$\mathrm{v} ightarrow \mathrm{bt} ightarrow \mathrm{bt}=\frac{	ext { distance }}{	ext { time }} ightarrow \mathrm{b} =\frac{	ext { distance }}{	ext { time }^{2}}$

$=	ext { acceration }$

$\mathrm{v} ightarrow \sqrt{\mathrm{ab}} \Rightarrow \mathrm{v}^{2}=\mathrm{ab} \Rightarrow \mathrm{a}=\frac{\mathrm{v}^{2}}{\mathrm{b}}=\frac{\mathrm{v}^{2}}{\mathrm{acc}}=\frac{\frac{\mathrm{s}^{2}}{\mathrm{t}^{2}}}{\frac{\mathrm{s}}{\mathrm{t}^{2}}}=\mathrm{s}$

$=\mathrm{distance}$

$\mathrm{d}+\mathrm{t} ightarrow \mathrm{t} \Rightarrow \mathrm{d} ightarrow \,time$

$\mathrm{v} ightarrow \frac{\mathrm{c}}{\mathrm{b}+\mathrm{t}}=\frac{\mathrm{c}}{\mathrm{t}} \Rightarrow \mathrm{c}=\mathrm{vt}=\frac{\mathrm{s}}{\mathrm{t}} 	imes \mathrm{t}=\mathrm{s} \Rightarrow \mathrm{c} ightarrow 	ext { distance } $

The velocity of a particle depends upon the time $t$ according to the equation $v = \sqrt {ab} + bt + \frac{c}{{d + t}}$ The physical quantities which are represented by $a, b, c$ and $d$, are in the following order

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