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9-1.Fluid Mechanics
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The velocity of a small ball of mass $M$ and density $d_1,$ when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is $d_2,$ the viscous force acting on the ball will be
A
$Mg\,\left( {1 - \frac{{{d_1}}}{{{d_2}}}} \right)$
B
$Mg\,\left( {1 - \frac{{{d_2}}}{{{d_1}}}} \right)$
C
$Mg\,\,d_1$
D
$Mg\,\,d_2$
Solution
At equilibrium, the viscous force acting upward $=$ Effective force downward
Effective force $=\mathrm{Vd}_{1} \mathrm{g}-\mathrm{Vd}_{2} \mathrm{g}=\mathrm{V}\left(\mathrm{d}_{1}-\mathrm{d}_{2}\right) \mathrm{g}$
$=\frac{M}{d_{1}}\left(d_{1}-d_{2}\right) g=M g\left[1-\frac{d_{2}}{d_{1}}\right]\left[\because V=\frac{M}{d_{1}}\right]$
Standard 11
Physics
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