The velocity$-$time graph of a truck is plotted below

$(a)$ Calculate the magnitude of displacement of the truck in $15$ seconds.

$(b)$ During which part of the journey was the truck decelerating ?

$(c)$ Calculate the magnitude of average velocity of the truck.

1151-116

Vedclass pdf generator app on play store
Vedclass iOS app on app store

$(a)$ Displacement $=$ area under the velocitytime graph, therefore, we Kave

$=\frac{1}{2} \times 5 \times 4+(12-5) \times 4+\frac{1}{2} \times(15-12) \times 4$

$=44 m$

$(b)$ During $12$ to $15$ second.

$(c)$ $V _{a v}=\frac{\text { displacement }}{\text { time }}=\frac{44}{15}=2.9 m s ^{-1}$

Similar Questions

Out of the three speed$-$time graphs shown below

Identify the graph for the following cases.

$(i)$ A ball thrown vertically upwards and returning to the hand of the thrower ?

$(ii)$ A body decelerating to a constant speed and accelerating.

For the motion on a straight line path with constant acceleration the ratio of the maqnitude of the displacement to the distance covered is

What is the nature of the displacement$-$time graph of a body moving with constant velocity ?

$(a)$ Derive graphically the equation for velocity$-$time relation.

$(b)$ Name the device used to measure distance travelled by a vehicle.

$(c)$ Can displacement of a moving object be zero ? Give reason.

What can you conclude about the motion of a body depicted by the velocity-time graphs $(i), (ii)$ and $(iii)$ given below ?