The velocity$-$time graph of a truck is plotted below
$(a)$ Calculate the magnitude of displacement of the truck in $15$ seconds.
$(b)$ During which part of the journey was the truck decelerating ?
$(c)$ Calculate the magnitude of average velocity of the truck.
$(a)$ Displacement $=$ area under the velocitytime graph, therefore, we Kave
$=\frac{1}{2} \times 5 \times 4+(12-5) \times 4+\frac{1}{2} \times(15-12) \times 4$
$=44 m$
$(b)$ During $12$ to $15$ second.
$(c)$ $V _{a v}=\frac{\text { displacement }}{\text { time }}=\frac{44}{15}=2.9 m s ^{-1}$
Out of the three speed$-$time graphs shown below
Identify the graph for the following cases.
$(i)$ A ball thrown vertically upwards and returning to the hand of the thrower ?
$(ii)$ A body decelerating to a constant speed and accelerating.
For the motion on a straight line path with constant acceleration the ratio of the maqnitude of the displacement to the distance covered is
What is the nature of the displacement$-$time graph of a body moving with constant velocity ?
$(a)$ Derive graphically the equation for velocity$-$time relation.
$(b)$ Name the device used to measure distance travelled by a vehicle.
$(c)$ Can displacement of a moving object be zero ? Give reason.
What can you conclude about the motion of a body depicted by the velocity-time graphs $(i), (ii)$ and $(iii)$ given below ?