Gujarati
Hindi
10-2.Transmission of Heat
normal

The wavelength of maximum energy released during an atomic explosion was $2.93\times10^{-10}\, m$. The maximum temperature attained must be, (Weins constant $= 2.93\times10^{-3}\, mK$)

A

$5.86\times10^7\, K$

B

$10^{-13}\, K$

C

$10^{-7}\, K$

D

$10^7\, K$

Solution

$\lambda_{\mathrm{m}} \times \mathrm{T}=\mathrm{b} \quad$ (Wein's displacement Law)

$\mathrm{T}=\frac{2.93 \times 10^{-3}}{2.93 \times 10^{-10}}=10^{7} \mathrm{\,K}$

Standard 11
Physics

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