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7.Gravitation
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The weight of a body on the surface of the earth is $100\,N$. The gravitational force on it when taken at a height, from the surface of earth, equal to onefourth the radius of the earth is $..........\,N$
A
$100$ $N$
B
$64$ $N$
C
$50$ $N$
D
$25$ $N$
(JEE MAIN-2023)
Solution
$\Rightarrow g^{\prime}=\frac{g R^2}{r^2}=\frac{g R^2}{\left(R+\frac{R}{4}\right)^2}=\frac{16 g}{25}$
$\therefore \text { Weight }=\frac{16}{25} \times 100=64\,N$
Standard 11
Physics
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