Weight of a person is 60, kg. If he gets 10^5 calories heat through food and efficiency of his body

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10-1.Thermometry, Thermal Expansion and Calorimetry

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The weight of a person is $60\, kg.$ If he gets $10^5$ calories heat through food and the efficiency of his body is $28\%,$ then upto how much height he can climb ........ $m$ (approximately)

A

$100$

B

$200 $

C

$400 $

D

$1000$

Solution

(b) Suppose person climbs upto height $h,$ then by using

$W = JQ$ $\Rightarrow$ $mgh = JQ$

$\Rightarrow$ $60 \times 9.8 \times h = 4.2 \times \left( {{{10}^5} \times \frac{{28}}{{100}}} \right)$ $\Rightarrow$ $h = 200\,m$

Standard 11

Physics

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