Work done in placing a charge of 8 × {10^{ - 18}} coulomb on a condenser of capacity 100, micro-far

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2. Electric Potential and Capacitance

easy

The work done in placing a charge of $8 \times {10^{ - 18}}$ coulomb on a condenser of capacity $100\, micro-farad$ is

A

$32 \times {10^{ - 32}}\,Joule$

B

$16 \times {10^{ - 32}}\,Joule$

C

$3.1 \times {10^{ - 26}}\,Joule$

D

$4 \times {10^{ - 10}}\,Joule$

(AIEEE-2003)

Solution

(a) $W = \frac{{{Q^2}}}{{2C}} = \frac{{{{(8 \times {{10}^{ – 18}})}^2}}}{{2 \times 100 \times {{10}^{ – 6}}}} = 32 \times {10^{ – 32}}J$

Standard 12

Physics

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