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6.Interest
medium
There is $60 \%$ increase in an amount in $6$ $years$ at simple interest. What will be the compound interest (In ₹) of ₹ $12000$ after $3$ years at the same rate?
A
$2160$
B
$3120$
C
$3972$
D
$6240$
Solution
S.I. for 6 years $=\frac{P \times 6 \times R}{100}=0.6 P$
Or
$R=\frac{0.6 \times 100}{6}=10 \%$
C.I. for 3 years for $₹ 12000 @ 10 \%$ p.a.
$\begin{array}{l}=12000\left[\left(1+\frac{10}{100}\right)^{3}-1\right]=12000\left[\left(\frac{11}{10}\right)^{3}-1\right] \\\left.=12000 \times \frac{(11)^{3}-(10)^{3}}{10^{3}}=12 \times(11-10)\left[(11)^{2}+(10)^{2}+110\right)\right] \\=12 \times 1 \times 331=₹ 3972\end{array}$
Standard 13
Quantitative Aptitude
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