There is 60 % increase in an amount in 6 year | vedclass

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Question

S.I. for 6 years $=\frac{P 	imes 6 	imes R}{100}=0.6 P$

Or

$R=\frac{0.6 	imes 100}{6}=10 \%$

C.I. for 3 years for $₹ 12000 @ 10 \%$ p.a.

Vedclass · Accepted Answer

$3972$

Vedclass · Answer

S.I. for 6 years $=\frac{P 	imes 6 	imes R}{100}=0.6 P$

Or

$R=\frac{0.6 	imes 100}{6}=10 \%$

C.I. for 3 years for $₹ 12000 @ 10 \%$ p.a.

$\begin{array}{l}=12000\left[\left(1+\frac{10}{100}ight)^{3}-1ight]=12000\left[\left(\frac{11}{10}ight)^{3}-1ight] \\left.=12000 	imes \frac{(11)^{3}-(10)^{3}}{10^{3}}=12 	imes(11-10)\left[(11)^{2}+(10)^{2}+110ight)ight] \=12 	imes 1 	imes 331=₹ 3972\end{array}$

There is $60 \%$ increase in an amount in $6$ $years$ at simple interest. What will be the compound interest (In ₹) of ₹ $12000$ after $3$ years at the same rate?

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