Three coins are tossed together, then probability of getting at least one head is

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14.Probability

easy

Three coins are tossed together, then the probability of getting at least one head is

A

$\frac{1}{2}$

B

$\frac{3}{4}$

C

$\frac{1}{8}$

D

$\frac{7}{8}$

Solution

(d) $P$ (at least one head) = $1 – P$ ($0$ head)

$ = 1 – P$ (All tail)$ = 1 – \frac{1}{8}$ $ = \frac{7}{8}$.

Standard 11

Mathematics

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