Three dice are thrown simultaneously. What is | vedclass

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Question

(c) Three dice can be thrown in $6 	imes 6 	imes 6 = 216$ ways.

A total $17$ can be obtained as $(5,\,6,\,6)$,$(6,\,5,\,6),$ $(6,\,6,\,5)$.

Vedclass · Accepted Answer

$\frac{1}{{54}}$

Vedclass · Answer

(c) Three dice can be thrown in $6 	imes 6 	imes 6 = 216$ ways.

A total $17$ can be obtained as $(5,\,6,\,6)$,$(6,\,5,\,6),$ $(6,\,6,\,5)$. 

A total $18$ can be obtained as $(6,\,6,\,6)$.

Hence the required probability $ = \frac{4}{{216}} = \frac{1}{{54}}.$

Three dice are thrown simultaneously. What is the probability of obtaining a total of $17$ or $18$

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