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4-1.Newton's Laws of Motion
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Three force $F_1=10\,N , F_2=8\,N , F _3=6\,N$ are acting on a particle of mass $5\,kg$. The forces $F _2$ and $F _3$ are applied perpendicular so that particle remains at rest. If the force $F_1$ is removed, then the acceleration of the particle is $......ms^{-2}$
A$2$
B$0.5$
C$4.8$
D$7$
(JEE MAIN-2023)
Solution
Resultant of $\overrightarrow{ F _2}$ and $\overrightarrow{ F _3}$ should be opposite to $\overrightarrow{ F _1}$
$a=\frac{10}{5}=2\,m / s ^2$
$a=\frac{10}{5}=2\,m / s ^2$
Standard 11
Physics
