Three particles A, B & C of equal mass mo | vedclass

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Question

In collision of these particles

Total momentum        $=$    Total momentum just

just before collision  &nbsp

Vedclass · Accepted Answer

$V$

Vedclass · Answer

In collision of these particles

Total momentum        $=$    Total momentum just

just before collision             after collisic

$\mathrm{m} \overrightarrow{\mathrm{V}}_{\mathrm{A}_{\mathrm{i}}}+\mathrm{m} \overrightarrow{\mathrm{V}}_{\mathrm{B}_{\mathrm{i}}}+\mathrm{m} \overrightarrow{\mathrm{V}}_{\mathrm{C}_{\mathrm{i}}}=\mathrm{O}+\left(-\mathrm{m} \overrightarrow{\mathrm{V}}_{\mathrm{B}_{\mathrm{i}}}ight)+\mathrm{m} \overrightarrow{\mathrm{V}}_{\mathrm{C}_{\mathrm{final}}}$

Initially all $3$ velocities are equal in magnitude and $120^{\circ}$ from each other so vector addition of $\overrightarrow{\mathrm{V}}_{\mathrm{A}_{i}}+\overrightarrow{\mathrm{V}}_{\mathrm{B}_{i}}+\overrightarrow{\mathrm{V}}_{\mathrm{C}_{i}}=0$

$	herefore \quad \mathrm{O}=\mathrm{O}+\left(-\mathrm{m} \overrightarrow{\mathrm{V}}_{\mathrm{B}_{i}}ight)+\mathrm{m} \overrightarrow{\mathrm{V}}_{\mathrm{C}_{\mathrm{Final}}}$

$	herefore \overrightarrow{\mathrm{V}}_{\mathrm{C}_{\mathrm{Final}}}=\overrightarrow{\mathrm{V}}_{\mathrm{B}_{1}}=\mathrm{V}$

Three particles $A, B$ & $C$ of equal mass move with speed $V$ as shown to strike at centroid of equilateral triangle after collision. $A$ comes to rest & $B$ retraces its path with speed $V$. speed of $C$ after collision is :-

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