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10-2.Transmission of Heat
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Three rods of same dimensions have thermal conductivities $3K,\,2K$ and $K$. They are arranged as shown with their ends at $100\,^oC$, $50\,^oC$ and $0\,^oC$. Temperature of junction is

A
$75\,^oC$
B
$\frac {200}{3}\,^oC$
C
$40\,^oC$
D
$\frac {100}{3}\,^oC$
Solution
Let temperature of junction be to
$\frac{\mathrm{T}_{0}-100}{\frac{\ell}{3 \mathrm{KA}}}+\frac{\mathrm{T}_{0}-50}{\frac{\ell}{2 \mathrm{KA}}}+\frac{\mathrm{T}_{0}-0}{\frac{\ell}{\mathrm{KA}}}=0$
$3 \mathrm{T}_{0}-300+2 \mathrm{T}_{0}-100+\mathrm{T}_{0}=0$
$6 \mathrm{T}_{0}=400$
$\mathrm{T}_{0}=\frac{400}{6}=\frac{200}{3}^{\circ} \mathrm{C}$
Standard 11
Physics
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