Two capacitors C₁ and C₂ are are charged to 120, V and 200, V respectively. It is found that by

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1. Electric Charges and Fields

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Two capacitors $C_1$ and $C_2$ are are charged to $120\, V$ and $200\, V$ respectively. It is found that by connecting them together the potential on each one can be made zero . Then

A

$3C_1 + 5C_2 = 0$

B

$9C_1 = 4C_2$

C

$5C_1 = 3C_2$

D

$3C_1 = 5C_2$

Solution

Potential can be made zero only if they have same charge.

$\Longrightarrow 120 C_{1}=200 C_{2}$

$\therefore 6 C_{1}=10 C_{2}$

$3 C_{1}=5 C_{2}$

Standard 12

Physics

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