Two capacitors $C_1$ and $C_2$ are are charged to $120\, V$ and $200\, V$ respectively. It is found that by connecting them together the potential on each one can be made zero . Then

  • A

    $3C_1 + 5C_2 = 0$

  • B

    $9C_1 = 4C_2$

  • C

    $5C_1 = 3C_2$

  • D

    $3C_1 = 5C_2$

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