Two condensers $C_1$ and $C_2$ in a circuit are joined as shown in figure. The  potential of point $A$ is $V_1$ and that of $B$ is $V_2$. The potential of point $D$ will be

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  • A

    $\frac{1}{2} (V_1 + V_2)$

  • B

    $\frac{{{C_2}{V_1} + {C_1}{V_2}}}{{{C_1} + {C_2}}}$

  • C

    $\frac{{{C_1}{V_1} + {C_2}{V_2}}}{{{C_1} + {C_2}}}$

  • D

    $\frac{{{C_2}{V_1} - {C_1}{V_2}}}{{{C_1} + {C_2}}}$

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