Two disc one of density 7.2, g/cm^3 and the o | vedclass

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Question

two disc having same mass and same thickness

$M=M$

$\mathrm{S}_{1} \cdot \pi_{1}^{2} \cdot \mathrm{t}=\mathrm{S}_{2} \cdot \pi_{2}^{2} \cdot \mathrm

Vedclass · Accepted Answer

$\frac{{8.9}}{{7.2}}$

Vedclass · Answer

two disc having same mass and same thickness

$M=M$

$\mathrm{S}_{1} \cdot \pi_{1}^{2} \cdot \mathrm{t}=\mathrm{S}_{2} \cdot \pi_{2}^{2} \cdot \mathrm{t} \Rightarrow \frac{\mathrm{r}_{1}^{2}}{\mathrm{r}_{2}^{2}}=\frac{\mathrm{S}_{2}}{\mathrm{S}_{1}}$

now the ratio of moment of inertia

$\frac{\mathrm{I}_{1}}{\mathrm{I}_{2}}=\frac{\frac{1}{2} \mathrm{Mr}_{1}^{2}}{\frac{1}{2} \mathrm{Mr}_{1}^{2}}=\frac{\mathrm{S}_{2}}{\mathrm{S}_{1}}=\frac{8.9}{7.2}$

Two disc one of density $7.2\, g/cm^3$ and the other of density $8.9\, g/cm^3$ are of same mass and thickness. Their moments of inertia are in the ratio

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