Two identical capacitors $1$ and $2$ are connected in series to a battery as shown in figure. Capacitor $2$ contains a dielectric slab of dielectric constant k as shown. $Q_1$ and $Q_2$ are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are $Q’_1$ and $Q’_2$. Then
Two identical capacitors $1$ and $2$ are connected in series to a battery as shown in figure. Capacitor $2$ contains a dielectric slab of dielectric constant k as shown. $Q_1$ and $Q_2$ are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are $Q’_1$ and $Q’_2$. Then
- A
$\frac{{{{Q'}_1}}}{{{Q_1}}} = \frac{{k + 1}}{k}$
- B
$\frac{{{{Q'}_2}}}{{{Q_2}}} = \frac{{k + 1}}{2}$
- C
$\frac{{{{Q'}_2}}}{{{Q_2}}} = \frac{{k + 1}}{{2k}}$
- D
$\frac{{{{Q'}_1}}}{{{Q_1}}} = \frac{k}{2}$
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