Two identical piano wires, kept under same tension T have a fundamental frequency of 600, Hz . fract

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14.Waves and Sound

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Two identical piano wires, kept under the same tension $T$ have a fundamental frequency of $600\, Hz$. The fractional increase in the tension of one of the wires which will lead to occurrence of $6\, beats/s$ when both the wires oscillate together would be

A

$0.01$

B

$0.02$

C

$0.03$

D

$0.04$

Solution

$ \mathrm{n} \propto \sqrt{\mathrm{T}} $

$\Rightarrow \frac{\Delta \mathrm{n}}{\mathrm{n}}=\frac{1}{2} \frac{\Delta \mathrm{T}}{\mathrm{T}} $

$\Rightarrow \frac{\Delta \mathrm{T}}{\mathrm{T}}=2\left(\frac{\Delta \mathrm{n}}{\mathrm{n}}\right) $

$=2\left(\frac{6}{600}\right)=0.02 $

Standard 11

Physics

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