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4-1.Newton's Laws of Motion
hard
Two objects $A$ and $B$ each of mass $m$ are connected by a light inextensible string. They are restricted to move on a frictionless ring of radius $R$ in a vertical plane (as shown in fig). The objects are released from rest at the position shown. Then, the tension in the cord just after release is

A
Zero
B
$mg$
C
$\sqrt 2\,mg$
D
$mg/ \sqrt 2$
Solution

$\frac{\mathrm{T}}{\sqrt{2}}=\mathrm{ma}$ ……$(1)$
$m g-\frac{T}{\sqrt{2}}=m a$ …….$(2)$
on solving: $T=\frac{m g}{\sqrt{2}}$
Standard 11
Physics