Gujarati
Hindi
4-1.Newton's Laws of Motion
hard

Two objects $A$ and $B$ each of mass $m$ are connected by a light inextensible string. They are restricted to move on a frictionless ring of radius $R$ in a vertical plane (as shown in fig). The objects are released from rest at the position shown. Then, the tension in the cord just after release is

A

Zero

B

$mg$

C

$\sqrt 2\,mg$

D

$mg/ \sqrt 2$

Solution

$\frac{\mathrm{T}}{\sqrt{2}}=\mathrm{ma}$     ……$(1)$

$m g-\frac{T}{\sqrt{2}}=m a$          …….$(2)$

on solving: $T=\frac{m g}{\sqrt{2}}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.