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1. Electric Charges and Fields
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Two parallel metal plates having charges $+ Q$ and $-Q$ face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will
A
Increase
B
Decrease
C
Remain same
D
Become zero
Solution
In kerosene tank capacitance increases and charge remains the same so potential difference and electric field will be decreased.
as $\quad \mathrm{Q}=\mathrm{CV}$
and $\mathrm{E}=\frac{\mathrm{V}}{\mathrm{d}}$
Standard 12
Physics
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