Gujarati
Hindi
1. Electric Charges and Fields
normal

Two parallel metal plates having charges $+ Q$ and $-Q$ face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will

A

Increase

B

Decrease

C

Remain same

D

Become zero

Solution

In kerosene tank capacitance increases and charge remains the same so potential difference and electric field will be decreased.

as $\quad \mathrm{Q}=\mathrm{CV}$

and $\mathrm{E}=\frac{\mathrm{V}}{\mathrm{d}}$

Standard 12
Physics

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