Gujarati
3-2.Motion in Plane
easy

Two particles of equal masses are revolving in circular paths of radii ${r_1}$ and ${r_2}$ respectively with the same speed. The ratio of their centripetal forces is

A$\frac{{{r_2}}}{{{r_1}}}$
B$\sqrt {\frac{{{r_2}}}{{{r_1}}}} $
C${\left( {\frac{{{r_1}}}{{{r_2}}}} \right)^2}$
D${\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^2}$

Solution

(a)$F = \frac{{m{v^2}}}{r}.$ If $m$ and $v$ are constants then
$F \propto \frac{1}{r}$
   $\frac{{{F_1}}}{{{F_2}}} = \left( {\frac{{{r_2}}}{{{r_1}}}} \right)$    
Standard 11
Physics

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