Two particles of masses $m_1$ and $m_2$ in projectile motion have velocities ${\vec v_1}$ and ${\vec v_2}$ respectively at time $t$ = $0$ . they collide at time $t_0$ . Their velocities become ${\vec v_1'}$ and ${\vec v_2'}$ at time $2t_0$ while still moving in air. The value of $\left| {\left( {{m_1}{{\vec v}_1}' + {m_2}{{\vec v}_2}'} \right) - \left( {{m_1}{{\vec v}_1} + {m_2}{{\vec v}_2}} \right)} \right|$ is
Zero
$(m_1 + m_2)gt_0$
$2(m_1 + m_2)gt_0$
$\frac {1}{2}(m_1 + m_2)gt_0$
A body of mass ${M}$ moving at speed ${V}_{0}$ collides elastically with a mass $'m'$ at rest. After the collision, the two masses move at angles $\theta_{1}$ and $\theta_{2}$ with respect to the initial direction of motion of the body of mass ${M}$. The largest possible value of the ratio ${M} / {m}$, for which the angles $\theta_{1}$ and $\theta_{2}$ will be equal, is :
$STATEMENT$-$1$ In an elastic collision between two bodies, the relative speed of the bodies after collision is equal to the relative speed before the collision. because
$STATEMENT$-$2$ In an elastic collision, the linear momentum of the system is conserved.
In an inelastic collision, what is conserved
What is head-on collision ?
As shown in the figure $a$ body of mass $m$ moving vertically with speed $3\, m/s$ hits a smooth fixed inclined plane and rebounds with a velocity $v_f$ in the horizontal direction. If $\angle$ of inclined is $30^o$, the velocity $v_f$ will be