Two rigid boxes containing different ideal gases are placed on a table. Box $A$ contains one mole of nitrogen at temperature $T_0$ , while box $B$ contains one mole of helium at temperature $(7/3)\, T_0$ . The boxes are then put into thermal contact with each other, and heat flows between them until the gases reach a common final temperature (ignore the heat capacity of boxes), then the final temperature of gases $T_f$ , in terms of $T_0$ is

  • A

    ${T_f} = \frac{3}{7}{T_0}$

  • B

    ${T_f} = \frac{7}{3}{T_0}$

  • C

    ${T_f} = \frac{3}{2}{T_0}$

  • D

    ${T_f} = \frac{5}{2}{T_0}$

Similar Questions

When a system is taken from state $i$ to state $f$ along the path $iaf,$ it is found that $Q = 50\, cal$ and $W = 20\, cal$. Along the path ibf $Q = 36\, cal$. Work done along the path $ibf$ will be ........... $\mathrm{cal}$

The internal energy change in a system that has absorbed $2\,\, kcal$ of heat and done $500\, J$ of work is ........... $\mathrm{J}$

Given diagram shows an ideal gas taken from state $1$ to $2$ through optional paths, $A,B,C.$ Let $Q,W$ and $U$ represent the heat supplied to, the work done by gas and the internal energy of the gas, respectively. Then which of the following conditions is true?

$1\, mole$ of an ideal gas at temperature $T_1$ expands according to the law $(P/V) =$ constant. Find the work done when the final temperature becomes $T_2$

In the indicator diagram (in figure), net amount of work done will be