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10-2.Transmission of Heat
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Two rods of same length and material transfer a given amount of heat in $12\, seconds$ , when they are joined end to end. But when they are joined in series, then they will transfer same heat in same conditions in........ $\sec$
A
$24$
B
$3$
C
$1.5$
D
$48$
Solution
$\frac{{{\rm{dQ}}}}{{12}} = \frac{{{\rm{k}}(2{\rm{A}})\left( {{{\rm{T}}_1} – {{\rm{T}}_2}} \right)}}{l}$ ….$(1)$
$\frac{{{\rm{d}}Q}}{{\rm{t}}} = \frac{{{\rm{kA}}\left( {{{\rm{T}}_1} – {{\rm{T}}_2}} \right)}}{{2l}}$ …..$(2)$
form $(1)$ and $(2)$
$ {\frac{\mathrm{t}}{12}=4} \,\,\, {\mathrm{t}=48 \mathrm{sec}}$
Standard 11
Physics
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