Gujarati
Hindi
10-2.Transmission of Heat
normal

Two rods of same length and material transfer a given amount of heat in $12\, seconds$ , when they are joined end to end. But when they are joined in series, then they will transfer same heat in same conditions in........ $\sec$

A

$24$

B

$3$

C

$1.5$

D

$48$

Solution

$\frac{{{\rm{dQ}}}}{{12}} = \frac{{{\rm{k}}(2{\rm{A}})\left( {{{\rm{T}}_1} – {{\rm{T}}_2}} \right)}}{l}$    ….$(1)$

$\frac{{{\rm{d}}Q}}{{\rm{t}}} = \frac{{{\rm{kA}}\left( {{{\rm{T}}_1} – {{\rm{T}}_2}} \right)}}{{2l}}$        …..$(2)$

form $(1)$ and $(2)$

$ {\frac{\mathrm{t}}{12}=4} \,\,\, {\mathrm{t}=48 \mathrm{sec}}$

Standard 11
Physics

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