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1. Electric Charges and Fields
easy
Two small conducting spheres of equal radius have charges $ + 10\,\mu C$ and $ - 20\,\mu C$ respectively and placed at a distance $R$ from each other experience force ${F_1}$. If they are brought in contact and separated to the same distance, they experience force ${F_2}$. The ratio of ${F_1}$ to ${F_2}$ is
A
$1:8$
B
$-8:1$
C
$1:2$
D
$-2:1$
Solution
(b) $F \propto {Q_1} {Q_2}$
$\frac{F_1}{F_2}$$ = \frac {{Q_1}{Q_2}} {{Q'_1}{Q'_2}}$$ = \frac{{10 \times – 20}}{{ – 5 \times – 5}} $$= \frac{{ – 8}}{1}$
Standard 12
Physics
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