Two springs of force constants $300\, N / m$ (Spring $A$) and $400$ $N / m$ (Spring $B$ ) are joined together in series. The combination is compressed by $8.75\, cm .$ The ratio of energy stored in $A$ and $B$ is $\frac{E_{A}}{E_{B}} .$ Then $\frac{E_{A}}{E_{B}}$ is equal to

  • [AIIMS 2019]
  • A

    $4 / 3$

  • B

    $16 / 9$

  • C

    $3 / 4$

  • D

    $9 / 6$

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  • [JEE MAIN 2021]

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