We are able to squeeze snow and make balls out of it because of

The apparent coefficient of expansion of a liquid when heated in a copper vessel is $C$ and when heated in a silver vessel is $S$. If $A$ is the linear coefficient of expansion of copper, then the linear coefficient of expansion of silver is

A beaker is completely filled with water at $4°C$. It will overflow if

A non-isotropic solid metal cube has coefficients of linear expansion as:

$5 \times 10^{-5} /^{\circ} \mathrm{C}$ along the $\mathrm{x}$ -axis and $5 \times 10^{-6} /^{\circ} \mathrm{C}$ along the $y$ and the $z-$axis. If the coefficient of volume expansion of the solid is $\mathrm{C} \times 10^{-6} /^{\circ} \mathrm{C}$ then the value of $\mathrm{C}$ is

We would like to make a vessel whose volume does not change with temperature (take a hint from the problem above). We can use brass and iron $\left( {{\beta _{{\text{v brass }}}} = 6 \times {{10}^{ - 5}}/K} \right.$ and $\left. {{\beta _{{\text{viron }}}} = 3.55 \times {{10}^{ - 5}}/K} \right)$ to create a volume of $100\,cc$ . How do you think you can achieve this.

The coefficients of thermal expansion of steel and a metal $X$ are respectively $12 × 10^{-6}$ and $2 × 10^{-6} per^o C$. At $40^o C$, the side of a cube of metal $X$ was measured using a steel vernier callipers. The reading was $100 \,\,mm$.Assuming that the calibration of the vernier was done at $0^o C$, then the actual length of the side of the cube at $0^o C$ will be