If the earth stops rotating, the value of $‘g’$ at the equator will

Find the magnitude of acceleration due to gravity at height of $10\, km$ from the surface of earth.

At a certain depth "$d$" below surface of earth. value of acceleration due to gravity becomes four times that of its value at a height $3\,R$ above earth surface. Where $R$ is Radius of earth (Take $R =6400\,km$ ). The depth $d$ is equal to $…………\,km$

The value of g on the earth's surface is $980\,cm/{\sec ^2}$. Its value at a height of $64 \,km$ from the earth's surface is …….. $cm/{\sec ^2}$

(Radius of the earth $R = 6400$ kilometers) 

Given below are two statements :

Statement$-I:$ Acceleration due to gravity is different at different places on the surface of earth.

Statement$-II:$ Acceleration due to gravity increases as we go down below the earth's surface.

In the light of the above statements, choose the correct answer from the options given below