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6.Interest
hard
What annual payment (In ₹) will discharge a debt of ₹ $1025$ due in $2$ years at the rate of $5 \%$ compound interest?
A
$550$
B
$551.25$
C
$560$
D
$560.75$
Solution
Let each annual instalment be ₹ $x$.
$\therefore \quad \frac{x}{\left(1+\frac{5}{100}\right)^{2}}+\frac{x}{\left(1+\frac{5}{100}\right)}=1025$
or $x \times\left(\frac{20}{21}\right)^{2}+x\left(\frac{20}{21}\right)=1025$
Or
$\frac{400 x}{441}+\frac{20 x}{21}=1025$
$\Rightarrow$
$\frac{400 x+420 x}{441}=1025$
or $x=\frac{1025 \times 441}{820}=₹ 551.25$
Hence each annual instalment $=₹ 551.25$
Standard 13
Quantitative Aptitude
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