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6-2.Equilibrium-II (Ionic Equilibrium)
medium
What is the minimum concentration of $SO_4^{2 - }$ required to precipitate $BaS{O_4}$ in a solution containing $1.0 \times {10^{ - 4}}\,mol\,\,\,B{a^{2 + }}$ (${K_{sp}}$ for $BaS{O_4}$ is $4 \times {10^{ - 10}}$)
A
$4 \times {10^{ - 10}}\,M$
B
$2 \times {10^{ - 7}}\,M$
C
$4 \times {10^{ - 6}}\,M$
D
$2 \times {10^{ - 3}}\,M$
Solution
(c) $BaS{O_4} $ $\rightleftharpoons$ $ B{a^{2 + }} + SO_4^{2 – }$
${K_{sp}} = {S^2} \Rightarrow S = \sqrt {{K_{sp}}} $;
${K_{sp}} = [B{a^{2 + }}] \times [SO_4^{2 – }]$
$4 \times {10^{ – 10}} = [1 \times {10^{ – 4}}] \times [SO_4^{2 – }]$
$[SO_4^{2 – }] = \frac{{4 \times {{10}^{ – 10}}}}{{1 \times {{10}^{ – 4}}}} = 4 \times {10^{ – 6}}$.
Standard 11
Chemistry
