6-2.Equilibrium-II (Ionic Equilibrium)
hard

What is the molar solubility of $Al(OH)_3$ in $0.2\, M\, NaOH$ solution? Given that, solubility product of $Al(OH)_3 = 2.4 \times 10^{-24}$ 

A

$3 \times {10^{ - 19}}$

B

$12 \times {10^{ - 21}}$

C

$12 \times {10^{ - 23}}$

D

$3 \times {10^{ - 22}}$

(JEE MAIN-2019)

Solution

$Al(O{H_3}) \rightleftharpoons \mathop {A{l^{3 + }}}\limits_s  + \mathop {3O{H^ – }}\limits_{(3s + 0.2)} $

$2.4 \times {10^{ – 24}} = s{(3s + 0.2)^3}$

Standard 11
Chemistry

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