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6-2.Equilibrium-II (Ionic Equilibrium)
hard
What is the molar solubility of $Al(OH)_3$ in $0.2\, M\, NaOH$ solution? Given that, solubility product of $Al(OH)_3 = 2.4 \times 10^{-24}$
A
$3 \times {10^{ - 19}}$
B
$12 \times {10^{ - 21}}$
C
$12 \times {10^{ - 23}}$
D
$3 \times {10^{ - 22}}$
(JEE MAIN-2019)
Solution
$Al(O{H_3}) \rightleftharpoons \mathop {A{l^{3 + }}}\limits_s + \mathop {3O{H^ – }}\limits_{(3s + 0.2)} $
$2.4 \times {10^{ – 24}} = s{(3s + 0.2)^3}$
Standard 11
Chemistry