What will be acceleration due to gravity at height h if h >> R . Where R is radius of earth an

English

Gujarati

Hindi

7.Gravitation

easy

What will be the acceleration due to gravity at height $h$ if $h >> R$. Where $R$ is radius of earth and $g$ is acceleration due to gravity on the surface of earth

A

$\frac{g}{{{{\left( {1 + \frac{h}{R}} \right)}^2}}}$

B

$g\left( {1 - \frac{{2h}}{R}} \right)$

C

$\frac{g}{{{{\left( {1 - \frac{h}{R}} \right)}^2}}}$

D

$g\left( {1 - \frac{h}{R}} \right)$

Solution

(a)$g' = g\,{\left( {\frac{R}{{R + h}}} \right)^2} = \frac{g}{{{{\left( {1 + \frac{h}{R}} \right)}^2}}}$

Standard 11

Physics

Share

Similar Questions

Obtain an expression for the variation in effective gravitational acceleration $g'$ with latitude due to earth’s rotation.

hard

At what distance from the centre of the earth, the value of acceleration due to gravity $g$ will be half that on the surface ($R =$ radius of earth)

medium

$Assertion$ : A tennis ball bounces higher on hills than in plains.
$Reason$ : Acceleration due to gravity on the hill is greater than that on the surface of earth

medium

(AIIMS-2009)

A body weighs $72 N$ on surface of the earth. When it is taken to a height of $h=2 R$, where $R$ is radius of earth, it would weigh …….. $N$

easy

The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes $1\%$ of its value at the surface is (Radius of the earth $= R$)

medium