What will be the compound interest (In ₹) on | vedclass

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Question

C.I. $=50000\left[\left(1+\frac{10}{100}\right)^{4}-1\right]$

$=50000\left[\left(\frac{11}{10}\right)^{4}-1\right]=\frac{50000}{10^{4}}\left[11^{4}

Vedclass · Accepted Answer

$23205$

Vedclass · Answer

C.I. $=50000\left[\left(1+\frac{10}{100}ight)^{4}-1ight]$

$=50000\left[\left(\frac{11}{10}ight)^{4}-1ight]=\frac{50000}{10^{4}}\left[11^{4}-10^{4}ight]$

$=5 	imes\left[\left(11^{2}+10^{2}ight)\left(11^{2}-10^{2}ight)ight]=5 	imes[221 	imes 21]=23205$

$	herefore$ Compound interest $=₹ 23205$

What will be the compound interest (In ₹) on a sum of ₹ $50000$ after $4$ years at the rate of $10 \%$ per annum?

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