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4-1.Newton's Laws of Motion
easy
When a $4 \,kg$ rifle is fired, the $10 \,g$ bullet receives an acceleration of $3 \times 10^6 \,cm / s ^2$. The magnitude of the force acting on the rifle (in newton) is ............
A
Zero
B
$120$
C
$300$
D
$3000$
Solution
(c)
Using Newton's third law, bullet will apply the same force in the opposite direction.
So, using $F=m a=\frac{10}{1000} \times 3 \times 10^6 \times 10^{-2}=300 \,N$
Standard 11
Physics