When a string is divided into three segments of length $l_1,\,l_2$ and $l_3,$ the fundamental frequencies of these three segments are $v_1,\,v_2$ and $v_3$ respectively. The original fundamental frequency $(v)$ of the string is
$\frac{1}{v} = \frac{1}{{{v_1}}} + \frac{1}{{{v_2}}} + \frac{1}{{{v_3}}}$
$\frac{1}{{\sqrt v }} = \frac{1}{{\sqrt {{v_1}} }} + \frac{1}{{\sqrt {{v_2}} }} + \frac{1}{{\sqrt {{v_3}} }}$
$\sqrt v = \sqrt {{v_1}} + \sqrt {{v_2}} + \sqrt {{v_3}} $
$v = v_1 + v_2 + v_3$
Four sources of sound each of sound level $10\,dB$ are sounded together, there sultant intensity level will be ... $dB$
A wave $y = a\,\sin \,\left( {\omega t - kx} \right)$ on a string meets with another wave producing a node at $x = 0$. Then the equation of the unknown wave is
A transverse wave is described by the equation $y = {y_0}\sin 2\pi \left( {ft - \frac{x}{\lambda }} \right)$. The maximum particle velocity is equal to four times wave velocity if
A sound absorber attenuates the sound level by $20\, dB$. The intensity decreases by a factor of
In a Fraunhofer's diffraction obtained by a single slit aperture, the value of path difference for $n^{th}$ order of minima is