Gujarati
Hindi
11.Thermodynamics
normal

When a system is taken from state $i$ to state $f$ along the path $iaf,$ it is found that $Q = 50\, cal$ and $W = 20\, cal$. Along the path ibf $Q = 36\, cal$. Work done along the path $ibf$ will be ........... $\mathrm{cal}$

A

$6$

B

$16$

C

$66$

D

$14$

Solution

By first law of thermodynamics:

$Q=\Delta U+W$

In path iaf:

$50=\Delta U +20$

$\therefore \quad \Delta U =30$

As this change in internal energy is between $i$ \& $f$ and does not depend on path.

Therefore along path ibf:

$Q =\Delta U + W$

$36=30+ W$

$\therefore \quad W =6\,cal$

Standard 11
Physics

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