When an air column at 15,^oC and a tunning fork are sounded together then 4 beats per second are pro

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14.Waves and Sound

hard

When an air column at $15\,^oC$ and a tunning fork are sounded together then $4$ beats per second are produced, the frequency of the fork is less then that of air column. When the temperature falls to $10\,^oC$ , then the beat frequency decreases by one. The frequency of the fork will be ..... $Hz$ $[V_{sound}$ at $0\,^oC = 332\,m/s]$

A

$110$

B

$114$

C

$113$

D

$106$

Solution

$\frac{{{{\rm{V}}_{15}}}}{{2l}} – {\rm{n}} = 4$

$\frac{{{{\rm{V}}_{10}}}}{{2l}} – {\rm{n}} = 3$

$\frac{V_{15}}{V_{10}}=\frac{n+4}{n+3}$ but $V_{t}=V_{0}+0.6 t$

$\frac{332+9}{332+6}=\frac{n+4}{n+3}$

$\mathrm{n}=110 \mathrm{\,Hz}$

Standard 11

Physics

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