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4.Chemical Bonding and Molecular Structure
hard
Which one of the following molecules is paramagnetic?
A
$N_2$
B
$NO$
C
$CO$
D
$O_3$
(JEE MAIN-2014)
Solution
The molecular orbital configuration of the molecules given is
Total no. of electrons in $NO$
$=7(N)+8(O)=15$
Hence $E.C.$ of $NO$
$KK{[\sigma 2s]^2}{[{\sigma ^*}(2s)]^2}{[\sigma 2{p_z}]^2}$
${[\pi (2{p_x})]^2}[\pi {(2{p_y})^2}]{[{\pi ^*}(2{p_x})]^1}$
Due to presence of one unpaired electron
$NO$ is paramagnetic.
Except $NO$ all are diamagnetic dur to absence of unpaired electrons.
Standard 11
Chemistry
