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Which option is correct for curve $a$ and $b$ ?
$[Image]$
Equation for equation for Type of Type of
Curve $(a)$ curve $(b)$ curve $(a)$ curve $(b)$

$\frac{d N}{d t}=r-N \frac{d N}{d t}=r N\left(\frac{N-K}{K}\right)$ Exponential curve Logistic curve
$\frac{d N}{d t}=r N \frac{d N}{d t}=r N\left(\frac{K-N}{K}\right)$ Exponential curve Logistic curve
$\frac{d N}{d t}=r N \frac{d N}{d t}=r N\left(\frac{K-N}{K}\right)$ S-shaped curve J-shaped curve
Both $(b)$ and $(c)$
Solution

$(b)$
Exponential growth curve is also called $J-$shaped curve or geometric growth curve.
Logistic curve is also called sigmoid growth curve $J-$shaped curve.
Exponential Growth Model When the resources availability is unlimited in the habitat, the population grows in an exponential or geometric fashion. As resources are unlimited than there is no inhibition from crowding.
The equation is; $d N / d t=(b-d) \times N i$ Birth rate, $d=i$, Death rate
$N=i$ Population density, $\frac{d n}{d t}=$ Rate of change of population
Let $(b-d)=r$, then the equation is, $d N / d t=R n$
$r=i$ Intrinsic rate of natural increase
When a population shows exponential growth, the curve plotted with $N$ in relation to time, assume J shape
In this there is no fix carrying capacity
Logistic Growth Model No population can continue to grow exponentially, as the resource availability become limiting at certain point of time. Logistic growth model have fixed carrying capacity
It is described by the equation $\frac{d N}{d t}=r N\left(\frac{K-N}{K}\right)$ Rate of change of population density
$N=$ Population density at time
$N=$ Population density
$r=$ Intrinsic rate of natural increase
$K=$ Carrying capacity
Population growth curve $A$ when resources are not limiting. Plot is exponential or geometrical curve $B$. When resources are limiting the growth, plot is logistic
$^{\prime} K ^{\prime}$ is carrying capacity