Why does (second)$^{2}$ occur in the unit of acceleration ?

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Acceleration $=\frac{\text { Change in velocity }}{\text { Time taken }}$

Unit of velocity and time is metre per second and second respectively. So Unit of acceleration

$=\frac{m s^{-1}}{s}=m s^{-2}$

Similar Questions

A body is moving along a circular path of radius $R$. Find the displacement of the body when it completes half a revolution.

A body moves with a velocity of $2\, m s ^{-1}$ for $5\, s$, then its velocity increases uniformly to $10\, m s ^{-1}$ in next $5\, s.$ Thereafter, its velocity begins to decrease at a uniform rate until it comes to rest after $5\, s$.

$(i)$ Plot a velocity-time graph for the motion of the body.

$(ii)$ From the graph, find the total distance covered by the body after $2\, s$ and $12\, s$.

Give an example of a body which covers a certain distance, but its displacement is zero

Velocity$-$time graph for the motion of an object in a straight path is a straight line parallel to the time axis.

$(a)$ Identify the nature of motion of the body.

$(b)$ Find the acceleration of the body.

$(c)$ Draw the shape of distance-time graph for this type of motion.

What can you conclude about the motion of a body depicted by the velocity-time graphs $(i), (ii)$ and $(iii)$ given below ?