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14.Probability
medium
Word ‘$UNIVERSITY$’ is arranged randomly. Then the probability that both ‘$I$’ does not come together, is
A
$\frac{3}{5}$
B
$\frac{2}{5}$
C
$\frac{4}{5}$
D
$\frac{1}{5}$
Solution
(c) Total number of ways $ = \frac{{10\,!}}{{2\,!}}$
Favourable number of ways for $'I'$ come together is $9\,!$
Thus probability that $'I'$ come together
$ = \frac{{9\,!\, \times \,2\,!}}{{10\,!}} = \frac{2}{{10}} = \frac{1}{5}$.
Hence required probability $ = 1 – \frac{1}{5} = \frac{4}{5}.$
Standard 11
Mathematics