In the $P-V$ diagram, $I$ is the initial state and $F$ is the final state. The gas goes from $I$ to $F$ by $(i)\,IAF,\,\,(ii)\,IBF,\,\,(iii) ICF$. The heat absorbed by the gas is

A monoatomic gas is taken along path $AB$ as shown. Calculate change in internal energy of system

The figure shows the $P-V$ plot of an ideal gas taken through a cycle $ABCDA$. The part $ABC$ is a semi-circle and $CDA$ is half of an ellipse. Then,

$(A)$ the process during the path $\mathrm{A} \rightarrow \mathrm{B}$ is isothermal

$(B)$ heat flows out of the gas during the path $\mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{D}$

$(C)$ work done during the path $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C}$ is zero

$(D)$ positive work is done by the gas in the cycle $ABCDA$

One mole of a monoatomic gas and one mole of a diatomic gas are initially in the same state. Both gases are expanded isothermally and then adiabatically, such that they acquire the same final state. Choose the correct statement.

Three moles of an ideal monoatomic gas perform a cycle as shown in the figure. The gas temperature in different states are: $T_1 = 400\, K, T_2 = 800\, K, T_3 = 2400\,K$ and $T_4 = 1200\,K.$ The work done by the gas during the cycle is …….. $kJ$