- Home
- Standard 11
- Physics
11.Thermodynamics
medium
Work done in the cyclic process shown in figure is ...........

A
$4 P_0 V_0$
B
$-4 P_0 V_0$
C
$-\frac{22}{7} P_0 V_0$
D
$-13 P_0 V_0$
Solution
(c)
Cyclic process is anticlockwise then
Work done $=-$ (Area of $P-V$ graph $)$
$W=-\pi R_1 R_2$
$=-\pi\left(\frac{3 P_0-P_0}{2}\right) \times\left(\frac{3 V_0-V_0}{2}\right)$
$=\frac{-22}{7} P_0 V_0$
Standard 11
Physics