11.Thermodynamics
medium

Work done in the cyclic process shown in figure is ...........

A

$4 P_0 V_0$

B

$-4 P_0 V_0$

C

$-\frac{22}{7} P_0 V_0$

D

$-13 P_0 V_0$

Solution

(c)

Cyclic process is anticlockwise then

Work done $=-$ (Area of $P-V$ graph $)$

$W=-\pi R_1 R_2$

$=-\pi\left(\frac{3 P_0-P_0}{2}\right) \times\left(\frac{3 V_0-V_0}{2}\right)$

$=\frac{-22}{7} P_0 V_0$

Standard 11
Physics

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