$2 x+5 y=20$

$\therefore 5 y=20-2 x$

$\therefore y=\frac{20-2 x}{5}$

Taking $x=0,$ we get $y=\frac{20-2(0)}{5}=\frac{20}{5}=4$

So, $(0,4)$ is a solution of the given equation.

Taking $x=5,$ we get $y=\frac{20-2(5)}{5}=\frac{10}{5}=2$

So, $(-5,6)$ is a solution of the given equation.

Taking $x=-5,$ we get

$y=\frac{20-2(-5)}{5}=\frac{30}{5}=6$

So, $(-5,6)$ is a solution of the given equation.

Taking $x=10,$ we get

$y=\frac{20-2(10)}{5}=\frac{0}{5}=0$

So, $(10,0)$ is a solution of the given equation.

So, four of the infinitely many solutions of the given equation are

$(0,4),(5,2),(-5,6) \text { and }(10,0)$